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The function f(x)=tan^(-1)(sinx+cosx) is...

The function `f(x)=tan^(-1)(sinx+cosx)` is an increasing function in `(-pi/2,pi/4)` (b) `(0,pi/2)` `(-pi/2,pi/2)` (d) `(pi/4,pi/2)`

A

`(0,(pi)/2)`

B

`-((pi)/2,(pi)/2)`

C

`((pi)/4,(pi)/2)`

D

`-((pi)/2,(pi)/4)`

Text Solution

Verified by Experts

The correct Answer is:
D

We have
`f(x)=tan^(-1)(sinx+cosx)`
`rArrf'(x)=1/(1+(sinx+cosx)^2)xx(cosx-sinx)`
`rArrf'(x)=cosx/(1+(sinx+cosx)^2)xx(1-tanx)`
Clearly ,f'(x) `gt 0 for all x in(-pi//2,pi//4)`
Hence f(x) is increasing in `(-pi//2,pi//4)`
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