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If 0 lt x lt pi /2 then...

`If 0 lt x lt pi /2 ` then

A

`tan x lt x lt sin x`

B

`x lt sin x lt tan x `

C

`sin x lt tan x lt x 1`

D

none of these

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The correct Answer is:
To solve the problem, we need to analyze the functions \( \tan x \), \( x \), and \( \sin x \) in the interval \( 0 < x < \frac{\pi}{2} \). We will determine their relationships by comparing their values and analyzing their graphs. ### Step 1: Understand the Functions We are looking at three functions: 1. \( \tan x \) 2. \( x \) 3. \( \sin x \) ### Step 2: Analyze the Interval The interval given is \( 0 < x < \frac{\pi}{2} \). In this interval: - \( \tan x \) is increasing and approaches infinity as \( x \) approaches \( \frac{\pi}{2} \). - \( \sin x \) is also increasing and approaches 1 as \( x \) approaches \( \frac{\pi}{2} \). - The line \( y = x \) is a straight line that increases linearly. ### Step 3: Graph the Functions To visualize the relationships: - Draw the graph of \( \sin x \) which starts at (0,0) and increases to (π/2, 1). - Draw the graph of \( \tan x \) which starts at (0,0) and increases rapidly, approaching infinity as \( x \) approaches \( \frac{\pi}{2} \). - Draw the line \( y = x \) which is a diagonal line from (0,0) to (π/2, π/2). ### Step 4: Compare the Functions In the interval \( 0 < x < \frac{\pi}{2} \): - At \( x = 0 \), \( \tan(0) = 0 \), \( \sin(0) = 0 \), and \( x = 0 \). - As \( x \) increases, \( \tan x \) increases faster than \( \sin x \) and the line \( y = x \). - We can use derivatives to confirm this: - The derivative of \( \tan x \) is \( \sec^2 x \), which is always positive in the interval. - The derivative of \( \sin x \) is \( \cos x \), which is also positive. - The derivative of \( x \) is 1, which is constant. ### Step 5: Establish the Relationships From the graphs and the analysis: - \( \tan x > x \) for \( 0 < x < \frac{\pi}{2} \) - \( x > \sin x \) for \( 0 < x < \frac{\pi}{2} \) Thus, we conclude: \[ \tan x > x > \sin x \quad \text{for} \quad 0 < x < \frac{\pi}{2} \] ### Final Answer The correct relationship is: \[ \tan x > x > \sin x \]

To solve the problem, we need to analyze the functions \( \tan x \), \( x \), and \( \sin x \) in the interval \( 0 < x < \frac{\pi}{2} \). We will determine their relationships by comparing their values and analyzing their graphs. ### Step 1: Understand the Functions We are looking at three functions: 1. \( \tan x \) 2. \( x \) 3. \( \sin x \) ...
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OBJECTIVE RD SHARMA ENGLISH-INCREASING AND DECREASING FUNCTIONS-Section I - Solved Mcqs
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