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If f(x)= underset(x)overset(x^2)int1/((l...

If `f(x)= underset(x)overset(x^2)int1/((log t)^2)dt ,x ne 1` then f(x)is monotomically

A

increasing on `(2,oo)`

B

incrasing on (1,2)

C

decreasing on `2(oo)`

D

decreasing on (0,3)

Text Solution

Verified by Experts

The correct Answer is:
A

We have
`f(x)=underset(x)overset(x^2)int(1)/((logt)^2)dt`
`rArr f(x)=2x(1)/((logx^2)^2)-1/((logx)^2)=((x-2)/(2))xx(1)/((log x)^2)`
Clearly `f(x) gt 0 " for all " x gt 2 `
Hence f(x) is increasing on `(2,oo)`
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