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The domain of definition of the function...

The domain of definition of the function `f(x)=sqrt(log_(10) ((2-x)/(x))) ` is

A

`(0, 1)`

B

`[0, 1 ]`

C

`(0, 1]`

D

`(0, 2 )`

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The correct Answer is:
To find the domain of the function \( f(x) = \sqrt{\log_{10} \left( \frac{2-x}{x} \right)} \), we need to ensure that the expression inside the square root is non-negative, as the square root function is only defined for non-negative values. ### Step-by-Step Solution: 1. **Set Up the Inequality**: We need to ensure that: \[ \log_{10} \left( \frac{2-x}{x} \right) \geq 0 \] 2. **Convert the Logarithmic Inequality**: The logarithm is non-negative when its argument is greater than or equal to 1: \[ \frac{2-x}{x} \geq 1 \] 3. **Rearranging the Inequality**: Multiply both sides by \( x \) (noting that \( x > 0 \) to avoid changing the direction of the inequality): \[ 2 - x \geq x \] This simplifies to: \[ 2 \geq 2x \] or \[ x \leq 1 \] 4. **Consider the Denominator**: Since \( x \) is in the denominator, we must also ensure that \( x \neq 0 \): \[ x > 0 \] 5. **Combine the Conditions**: We have two conditions: - \( x \leq 1 \) - \( x > 0 \) Combining these gives: \[ 0 < x \leq 1 \] 6. **Express the Domain**: The domain of the function \( f(x) \) is: \[ (0, 1] \] ### Final Answer: The domain of the function \( f(x) = \sqrt{\log_{10} \left( \frac{2-x}{x} \right)} \) is \( (0, 1] \).

To find the domain of the function \( f(x) = \sqrt{\log_{10} \left( \frac{2-x}{x} \right)} \), we need to ensure that the expression inside the square root is non-negative, as the square root function is only defined for non-negative values. ### Step-by-Step Solution: 1. **Set Up the Inequality**: We need to ensure that: \[ \log_{10} \left( \frac{2-x}{x} \right) \geq 0 ...
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