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Find the equation of the plane through t...

Find the equation of the plane through the points `A(2,2,-1),B(3,4,2)a n dC(7,0,6.)`

A

`5x+2y+3z=17`

B

`5x+2y-3z=17`

C

`5x-2y+3z=17`

D

none of these

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To find the equation of the plane passing through the points \( A(2,2,-1) \), \( B(3,4,2) \), and \( C(7,0,6) \), we can follow these steps: ### Step 1: Find the vectors \( \vec{AB} \) and \( \vec{BC} \) The vectors can be calculated as follows: \[ \vec{AB} = B - A = (3 - 2, 4 - 2, 2 - (-1)) = (1, 2, 3) \] \[ \vec{BC} = C - B = (7 - 3, 0 - 4, 6 - 2) = (4, -4, 4) \] ### Step 2: Find the normal vector \( \vec{n} \) using the cross product \( \vec{AB} \times \vec{BC} \) The cross product can be calculated using the determinant of a matrix formed by the unit vectors \( \hat{i}, \hat{j}, \hat{k} \) and the components of \( \vec{AB} \) and \( \vec{BC} \): \[ \vec{n} = \vec{AB} \times \vec{BC} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ 1 & 2 & 3 \\ 4 & -4 & 4 \end{vmatrix} \] Calculating the determinant: \[ \vec{n} = \hat{i} \begin{vmatrix} 2 & 3 \\ -4 & 4 \end{vmatrix} - \hat{j} \begin{vmatrix} 1 & 3 \\ 4 & 4 \end{vmatrix} + \hat{k} \begin{vmatrix} 1 & 2 \\ 4 & -4 \end{vmatrix} \] Calculating each of these determinants: 1. \( \hat{i} (2 \cdot 4 - 3 \cdot (-4)) = \hat{i} (8 + 12) = 20\hat{i} \) 2. \( -\hat{j} (1 \cdot 4 - 3 \cdot 4) = -\hat{j} (4 - 12) = 8\hat{j} \) 3. \( \hat{k} (1 \cdot (-4) - 2 \cdot 4) = \hat{k} (-4 - 8) = -12\hat{k} \) So, \[ \vec{n} = 20\hat{i} + 8\hat{j} - 12\hat{k} \] ### Step 3: Write the equation of the plane The general equation of a plane can be expressed as: \[ n_1(x - x_0) + n_2(y - y_0) + n_3(z - z_0) = 0 \] Where \( (x_0, y_0, z_0) \) is a point on the plane (we can use point \( A(2, 2, -1) \)) and \( (n_1, n_2, n_3) \) are the components of the normal vector \( \vec{n} \). Substituting the values: \[ 20(x - 2) + 8(y - 2) - 12(z + 1) = 0 \] Expanding this: \[ 20x - 40 + 8y - 16 - 12z - 12 = 0 \] Combining like terms: \[ 20x + 8y - 12z - 68 = 0 \] ### Final Equation The equation of the plane is: \[ 20x + 8y - 12z = 68 \]

To find the equation of the plane passing through the points \( A(2,2,-1) \), \( B(3,4,2) \), and \( C(7,0,6) \), we can follow these steps: ### Step 1: Find the vectors \( \vec{AB} \) and \( \vec{BC} \) The vectors can be calculated as follows: \[ \vec{AB} = B - A = (3 - 2, 4 - 2, 2 - (-1)) = (1, 2, 3) \] ...
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OBJECTIVE RD SHARMA ENGLISH-PLANE AND STRAIGHT LINE IN SPACE -Chapter Test
  1. Find the equation of the plane through the points A(2,2,-1),B(3,4,2)a ...

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  2. The length of the perpendicular from the origin to the plane passing t...

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  3. The value of lamda for which the lines (x-1)/1=(y-2)/(lamda)=(z+1)/(-1...

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  4. The angle between the lines (x+4)/(1) = (y-3)/(2) = (z+2)/(3) and (x)/...

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  5. The direction cosines of the line 6x-2=3y+1=2z-2 are

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  6. A line passes through two points A(2,-3,-1) and B(8,-1,2). The coordin...

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  7. The position vector of a point at a distance of 3sqrt(11) units from h...

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  8. The line joining the points 6veca-4vecb+4vecc, -4vecc and the line joi...

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  9. The image (or reflection) of the point (1,2-1) in the plane vecr.(3hat...

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  10. The equation of the plane through the line of intersection of the plan...

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  11. Angle between the line vecr=(2hati-hatj+hatk)+lamda(-hati+hatj+hatk) a...

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  12. The line through hati+3hatj+2hatkandbot"to the line "vecr=(hati+2hatj-...

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  13. The distance of the point having position vector -hat(i) + 2hat(j) + 6...

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  14. The position vector of the point in which the line joining the points ...

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  15. The two lines vecr=veca+veclamda(vecbxxvecc) and vecr=vecb+mu(veccxxve...

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  16. Lines vecr = veca(1) + lambda vecb and vecr = veca(2) + svecb will lie...

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  17. Equation of a line passing through (-1,2,-3) and perpendicular to the ...

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  18. Find the Vector and Cartesian equation of line passing through (1, -2,...

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  19. The distance between the planes given by vecr.(hati+2hatj-2hatk)+5=0...

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  20. Find shortest distance between the line vecr = (5hati + 7hatj + 3ha...

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  21. Find the shortest distance between the lines vecr=(hatii+2hatj+hatk)+l...

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