Find the angle between the lines `(x-2)/3=(y+1)/(-2)=z=2a n d(x-1)/1=(2y+3)/3=(z+5)/2dot`

Options

A. `(pi)/6`
B. `(pi)/4`
C. `(pi)/2`
D. `(pi)/3`

Answer

C

Explanation

The given equations are not in the standard form.
The equations of the given lines in standard form can be written as
`(x-2)/3=(y+1)/(-2)=(z-2)/0`…………..i
and `(x-1)/1=(y+3//2)/(3//2)=(z+5)/2`…………..ii
If `theta` is the angle the given lines, then
`cos theta=((3)(1)+(-2)(3//2)+(0)(2))/(sqrt(3^(2)+(-2)^(2)+0^(2))sqrt(1^(2)+(3//2)^(2)+2^(2)))-0`
`impliestheta=pi//2`