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The lines x/1=y/2=z/3 and (x-1)/(-2)=(y-...

The lines `x/1=y/2=z/3` and `(x-1)/(-2)=(y-2)/(-4)=(z-3)/(-6)` are

A

coincident

B

skew

C

intersecting

D

parallel

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The correct Answer is:
To determine the relationship between the lines given by the equations \( \frac{x}{1} = \frac{y}{2} = \frac{z}{3} \) and \( \frac{x-1}{-2} = \frac{y-2}{-4} = \frac{z-3}{-6} \), we will follow these steps: ### Step 1: Identify the direction ratios of the lines For the first line, \( \frac{x}{1} = \frac{y}{2} = \frac{z}{3} \), the direction ratios can be directly read as: - \( b_1 = (1, 2, 3) \) For the second line, \( \frac{x-1}{-2} = \frac{y-2}{-4} = \frac{z-3}{-6} \), the direction ratios are: - \( b_2 = (-2, -4, -6) \) ### Step 2: Check if the direction ratios are proportional To check if the lines are parallel, we need to see if the direction ratios \( b_1 \) and \( b_2 \) are proportional. This means we need to find a scalar \( k \) such that: \[ b_1 = k \cdot b_2 \] Calculating the proportionality: - If we take \( k = -\frac{1}{2} \), then: \[ k \cdot b_2 = -\frac{1}{2} \cdot (-2, -4, -6) = (1, 2, 3) = b_1 \] Since \( b_1 \) is proportional to \( b_2 \), we conclude that the lines are parallel. ### Step 3: Conclusion Since the direction ratios of the two lines are proportional, we can conclude that the lines are parallel. ### Final Answer: The lines are **parallel**. ---

To determine the relationship between the lines given by the equations \( \frac{x}{1} = \frac{y}{2} = \frac{z}{3} \) and \( \frac{x-1}{-2} = \frac{y-2}{-4} = \frac{z-3}{-6} \), we will follow these steps: ### Step 1: Identify the direction ratios of the lines For the first line, \( \frac{x}{1} = \frac{y}{2} = \frac{z}{3} \), the direction ratios can be directly read as: - \( b_1 = (1, 2, 3) \) For the second line, \( \frac{x-1}{-2} = \frac{y-2}{-4} = \frac{z-3}{-6} \), the direction ratios are: ...
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OBJECTIVE RD SHARMA ENGLISH-PLANE AND STRAIGHT LINE IN SPACE -Chapter Test
  1. The lines x/1=y/2=z/3 and (x-1)/(-2)=(y-2)/(-4)=(z-3)/(-6) are

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  2. The length of the perpendicular from the origin to the plane passing t...

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  3. The value of lamda for which the lines (x-1)/1=(y-2)/(lamda)=(z+1)/(-1...

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  4. The angle between the lines (x+4)/(1) = (y-3)/(2) = (z+2)/(3) and (x)/...

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  5. The direction cosines of the line 6x-2=3y+1=2z-2 are

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  6. A line passes through two points A(2,-3,-1) and B(8,-1,2). The coordin...

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  7. The position vector of a point at a distance of 3sqrt(11) units from h...

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  8. The line joining the points 6veca-4vecb+4vecc, -4vecc and the line joi...

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  9. The image (or reflection) of the point (1,2-1) in the plane vecr.(3hat...

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  10. The equation of the plane through the line of intersection of the plan...

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  11. Angle between the line vecr=(2hati-hatj+hatk)+lamda(-hati+hatj+hatk) a...

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  12. The line through hati+3hatj+2hatkandbot"to the line "vecr=(hati+2hatj-...

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  13. The distance of the point having position vector -hat(i) + 2hat(j) + 6...

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  14. The position vector of the point in which the line joining the points ...

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  15. The two lines vecr=veca+veclamda(vecbxxvecc) and vecr=vecb+mu(veccxxve...

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  16. Lines vecr = veca(1) + lambda vecb and vecr = veca(2) + svecb will lie...

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  17. Equation of a line passing through (-1,2,-3) and perpendicular to the ...

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  18. Find the Vector and Cartesian equation of line passing through (1, -2,...

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  19. The distance between the planes given by vecr.(hati+2hatj-2hatk)+5=0...

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  20. Find shortest distance between the line vecr = (5hati + 7hatj + 3ha...

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  21. Find the shortest distance between the lines vecr=(hatii+2hatj+hatk)+l...

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