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Distance between two parallel planes `2x""+""y""+""2z""=""8` and `4x""+""2y""+""4z""+""5""=""0` is (1) `5/2` (2) `7/2` (3) `9/2` (4) `3/2`

A

`3/2`

B

`5/2`

C

`7/2`

D

`9/2`

Text Solution

AI Generated Solution

The correct Answer is:
To find the distance between the two parallel planes given by the equations \(2x + y + 2z = 8\) and \(4x + 2y + 4z + 5 = 0\), we will follow these steps: ### Step 1: Rewrite the equations of the planes First, we need to express both plane equations in the standard form \(Ax + By + Cz + D = 0\). 1. For the first plane: \[ 2x + y + 2z - 8 = 0 \] This can be written as: \[ 2x + y + 2z + (-8) = 0 \] Here, \(D_1 = -8\). 2. For the second plane: \[ 4x + 2y + 4z + 5 = 0 \] This can be written as: \[ 4x + 2y + 4z + 5 = 0 \] Here, \(D_2 = 5\). ### Step 2: Check if the planes are parallel To check if the planes are parallel, we need to compare their normal vectors. - The normal vector for the first plane is \((2, 1, 2)\). - The normal vector for the second plane is \((4, 2, 4)\). Since \((4, 2, 4) = 2 \cdot (2, 1, 2)\), the planes are parallel. ### Step 3: Use the distance formula for parallel planes The formula for the distance \(d\) between two parallel planes \(Ax + By + Cz + D_1 = 0\) and \(Ax + By + Cz + D_2 = 0\) is given by: \[ d = \frac{|D_2 - D_1|}{\sqrt{A^2 + B^2 + C^2}} \] ### Step 4: Substitute values into the formula 1. Identify coefficients \(A\), \(B\), and \(C\): - From the first plane, \(A = 2\), \(B = 1\), \(C = 2\). 2. Calculate \(D_2 - D_1\): \[ D_2 - D_1 = 5 - (-8) = 5 + 8 = 13 \] 3. Calculate the denominator: \[ \sqrt{A^2 + B^2 + C^2} = \sqrt{2^2 + 1^2 + 2^2} = \sqrt{4 + 1 + 4} = \sqrt{9} = 3 \] 4. Substitute into the distance formula: \[ d = \frac{|13|}{3} = \frac{13}{3} \] ### Step 5: Final calculation Thus, the distance between the two parallel planes is: \[ d = \frac{13}{3} \] ### Conclusion After checking the options provided, it seems the calculated distance does not match any of the options given. However, based on the correct application of the formula, the distance is \(\frac{13}{3}\).

To find the distance between the two parallel planes given by the equations \(2x + y + 2z = 8\) and \(4x + 2y + 4z + 5 = 0\), we will follow these steps: ### Step 1: Rewrite the equations of the planes First, we need to express both plane equations in the standard form \(Ax + By + Cz + D = 0\). 1. For the first plane: \[ 2x + y + 2z - 8 = 0 ...
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OBJECTIVE RD SHARMA ENGLISH-PLANE AND STRAIGHT LINE IN SPACE -Chapter Test
  1. Distance between two parallel planes 2x""+""y""+""2z""=""8 and 4x"...

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  2. The length of the perpendicular from the origin to the plane passing t...

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  3. The value of lamda for which the lines (x-1)/1=(y-2)/(lamda)=(z+1)/(-1...

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  4. The angle between the lines (x+4)/(1) = (y-3)/(2) = (z+2)/(3) and (x)/...

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  5. The direction cosines of the line 6x-2=3y+1=2z-2 are

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  6. A line passes through two points A(2,-3,-1) and B(8,-1,2). The coordin...

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  7. The position vector of a point at a distance of 3sqrt(11) units from h...

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  8. The line joining the points 6veca-4vecb+4vecc, -4vecc and the line joi...

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  9. The image (or reflection) of the point (1,2-1) in the plane vecr.(3hat...

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  10. The equation of the plane through the line of intersection of the plan...

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  11. Angle between the line vecr=(2hati-hatj+hatk)+lamda(-hati+hatj+hatk) a...

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  12. The line through hati+3hatj+2hatkandbot"to the line "vecr=(hati+2hatj-...

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  13. The distance of the point having position vector -hat(i) + 2hat(j) + 6...

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  14. The position vector of the point in which the line joining the points ...

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  15. The two lines vecr=veca+veclamda(vecbxxvecc) and vecr=vecb+mu(veccxxve...

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  16. Lines vecr = veca(1) + lambda vecb and vecr = veca(2) + svecb will lie...

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  17. Equation of a line passing through (-1,2,-3) and perpendicular to the ...

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  18. Find the Vector and Cartesian equation of line passing through (1, -2,...

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  19. The distance between the planes given by vecr.(hati+2hatj-2hatk)+5=0...

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  20. Find shortest distance between the line vecr = (5hati + 7hatj + 3ha...

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  21. Find the shortest distance between the lines vecr=(hatii+2hatj+hatk)+l...

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