Statement-I The lines `(x-1)/(1)=(y)/(-1)=(z+1)/(1) and (x-2)/(1)=(y+1)/(2)=(z)/(3)` are coplanar and equation of the plane containing them is `5x+2y-3z-8=0`
Statement-II The line `(x-2)/(1)=(y+1)/(2)=(z)/(3)` is perpendicular to the plane `3x+6y+9z-8=0` and parallel to the plane `x+y-z=0`.

Options

A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1.
B. Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for Statement-1.
C. Statement-1 is True, Statement-2 is False.
D. Statement-1 is False, Statement-2 is True.

Answer

B

Explanation

Lines is statement -1 pass through (1,0,-1) and (2,-1,0) respectively.
We have
`|(2-1,-1-0 ,0+1),(1,-1,1),(1,2,3)|=5+2+3=0`
So the given lines are coplanar.
The equation of the plane containing them is
`|(x-1,y,z+1),(1,-1,1),(1,2,3)|=0`
`implies -5x+5-2y+3z+3=0implies5x+2y-3z-8=0`
So statement -1 is true.
A vector parallel to the given line is `vecb=hati+2hatj+3hatk` and vectors normals to given planes are `vecn_(1)=3hati+6hatj+9hatk` and `vecn_(2)=hati+hatj-hatk` respectively.
Clearly` vecn_(1)=3vecb` and `vecb.vecn=0`
So, give line is perpendicular to `3x+6y+9z-8=0` and parallel to `x+y-z=0`
Hece statement -2 is true.