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The equation of the plane passing throug...

The equation of the plane passing through three non - collinear points with positions vectors a,b,c, is

A

`vecr.(vecaxxvecb+vecbxxvecc+veccxxveca)=0`

B

`vecrxx(vecaxxvecb+vecbxxvecc)=[(veca,vecb,vecc)]`

C

`vecr.(vecaxxvecb+vecbxxvecc+veccxxveca)+[(veca,vecb,vecc)]=0`

D

none of these

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The correct Answer is:
To find the equation of the plane passing through three non-collinear points with position vectors **a**, **b**, and **c**, we can follow these steps: ### Step 1: Define the Position Vector of a Point on the Plane Let **R** be the position vector of any point on the plane. The vectors **a**, **b**, and **c** represent three points in space. ### Step 2: Formulate the Vector Equation The vector equation of the plane can be expressed using the position vectors of the points. We can express the vector **R** in terms of the vectors **a**, **b**, and **c**: \[ \text{R} - \text{a} = \lambda (\text{b} - \text{a}) + \mu (\text{c} - \text{a}) \] where \(\lambda\) and \(\mu\) are scalars. ### Step 3: Rearranging the Equation Rearranging the equation gives: \[ \text{R} = \text{a} + \lambda (\text{b} - \text{a}) + \mu (\text{c} - \text{a}) \] ### Step 4: Use the Cross Product to Find the Normal Vector The normal vector to the plane can be found using the cross product of two vectors lying in the plane: \[ \text{n} = (\text{b} - \text{a}) \times (\text{c} - \text{a}) \] ### Step 5: Write the Equation of the Plane The general equation of a plane can be written as: \[ \text{n} \cdot (\text{R} - \text{a}) = 0 \] Substituting the normal vector: \[ ((\text{b} - \text{a}) \times (\text{c} - \text{a})) \cdot (\text{R} - \text{a}) = 0 \] ### Step 6: Expand the Equation Expanding this gives: \[ (\text{b} - \text{a}) \times (\text{c} - \text{a}) \cdot \text{R} - (\text{b} - \text{a}) \times (\text{c} - \text{a}) \cdot \text{a} = 0 \] ### Step 7: Final Form The final equation of the plane can be expressed as: \[ \text{R} \cdot ((\text{b} - \text{a}) \times (\text{c} - \text{a})) = \text{a} \cdot ((\text{b} - \text{a}) \times (\text{c} - \text{a})) \] ### Summary Thus, the equation of the plane passing through the points with position vectors **a**, **b**, and **c** is: \[ \text{R} \cdot ((\text{b} - \text{a}) \times (\text{c} - \text{a})) = \text{a} \cdot ((\text{b} - \text{a}) \times (\text{c} - \text{a})) \]

To find the equation of the plane passing through three non-collinear points with position vectors **a**, **b**, and **c**, we can follow these steps: ### Step 1: Define the Position Vector of a Point on the Plane Let **R** be the position vector of any point on the plane. The vectors **a**, **b**, and **c** represent three points in space. ### Step 2: Formulate the Vector Equation The vector equation of the plane can be expressed using the position vectors of the points. We can express the vector **R** in terms of the vectors **a**, **b**, and **c**: \[ ...
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OBJECTIVE RD SHARMA ENGLISH-PLANE AND STRAIGHT LINE IN SPACE -Exercise
  1. Find the vector equation of the plane in which the lines vecr=hati+ha...

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  2. The Cartesian equation of the plane vecr=(1+lamda-mu)hati+(2-lamda)hat...

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  3. The perpendicular distance between the line vecr = 2hati-2hatj+3hatk+l...

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  4. The vector equation of the line of intersection of the planes vecr.(2h...

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  5. A straight line vecr=veca+lambda vecb meets the plane vecr. vec n=0 at...

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  6. The equation of the plane passing through three non - collinear points...

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  7. The length of the perpendicular from the origin to the plane passing t...

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  8. The equation of the plane containing the line (x-x1)/l=(y-y1)/m=(z-...

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  9. Find the shortest distance between the following pairs of lines whose ...

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  10. If the lines (x-1)/(-3)=(y-2)/(2k)=(z-3)/2and (x-1)/(3k)=(y-1)/1=(z-6...

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  11. The direction ratios of a normal to the plane passing throuhg (0,0,1)...

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  12. A variable plane is at a distance, k from the origin and meets the coo...

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  13. Find the equation of the plane perpendicular to the line (x-1)/2=(y...

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  14. Find the equation of the plane through the points (2,2,1) and (9,3,6) ...

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  15. The equation of the plane containing the two lines (x-1)/2=(y+1)/(-1...

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  16. The direction ratios of the normal to the plane passing through the po...

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  17. The equation of a plane through the point (2, 3, 1) and (4, -5, 3) a...

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  18. The angle between the lines (x+4)/(1) = (y-3)/(2) = (z+2)/(3) and (x)/...

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  19. The equation of the plane which is perpendicular bisector of the line ...

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  20. If the position vectors of the point A and B are 3hat(i)+hat(j)+2hat(k...

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