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The length of the perpendicular from the...

The length of the perpendicular from the origin to the plane passing though three non-collinear points `veca,vecb,vecc` is

A

`([(veca,vecb,vecc)])/(|vecaxxvecb+veccxxveca+vecbxxvecc|)`

B

`(2[(veca,vecb,vecc)])/(|vecaxxvecb+vecbxxvecc+veccxxveca|)`

C

`[(veca,vecb,vecc)]`

D

none of these

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The correct Answer is:
To find the length of the perpendicular from the origin to the plane passing through three non-collinear points represented by vectors \(\vec{a}\), \(\vec{b}\), and \(\vec{c}\), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Points**: We have three non-collinear points represented by vectors \(\vec{a}\), \(\vec{b}\), and \(\vec{c}\). 2. **Determine the Normal Vector**: The normal vector to the plane formed by these three points can be found using the cross product of two vectors that lie on the plane. We can take the vectors \(\vec{b} - \vec{a}\) and \(\vec{c} - \vec{b}\): \[ \vec{n} = (\vec{b} - \vec{a}) \times (\vec{c} - \vec{b}) \] 3. **Equation of the Plane**: The equation of the plane can be expressed in the form: \[ \vec{r} - \vec{a} \cdot \vec{n} = 0 \] This can be rearranged to: \[ \vec{r} \cdot \vec{n} = \vec{a} \cdot \vec{n} \] 4. **Finding the Length of the Perpendicular**: The length of the perpendicular from the origin (point \(\vec{0}\)) to the plane can be calculated using the formula: \[ \text{Length} = \frac{|\vec{a} \cdot \vec{n}|}{|\vec{n}|} \] Here, \(\vec{n}\) is the normal vector we computed in step 2. 5. **Substituting Values**: We can express \(\vec{n}\) in terms of the vectors: \[ \vec{n} = (\vec{b} - \vec{a}) \times (\vec{c} - \vec{b}) \] Then, substituting this into the length formula gives: \[ \text{Length} = \frac{|\vec{a} \cdot ((\vec{b} - \vec{a}) \times (\vec{c} - \vec{b}))|}{|(\vec{b} - \vec{a}) \times (\vec{c} - \vec{b})|} \] 6. **Final Expression**: After simplifying, we arrive at the final expression for the length of the perpendicular from the origin to the plane: \[ \text{Length} = \frac{|\vec{a} \cdot \vec{n}|}{|\vec{n}|} = \frac{\vec{a} \cdot \vec{b} \times \vec{c}}{|\vec{b} \times \vec{c}|} \] ### Final Result: The length of the perpendicular from the origin to the plane is given by: \[ \text{Length} = \frac{\vec{a} \cdot (\vec{b} \times \vec{c})}{|\vec{b} \times \vec{c}|} \]

To find the length of the perpendicular from the origin to the plane passing through three non-collinear points represented by vectors \(\vec{a}\), \(\vec{b}\), and \(\vec{c}\), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Points**: We have three non-collinear points represented by vectors \(\vec{a}\), \(\vec{b}\), and \(\vec{c}\). 2. **Determine the Normal Vector**: The normal vector to the plane formed by these three points can be found using the cross product of two vectors that lie on the plane. We can take the vectors \(\vec{b} - \vec{a}\) and \(\vec{c} - \vec{b}\): \[ ...
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OBJECTIVE RD SHARMA ENGLISH-PLANE AND STRAIGHT LINE IN SPACE -Exercise
  1. Find the vector equation of the plane in which the lines vecr=hati+ha...

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  2. The Cartesian equation of the plane vecr=(1+lamda-mu)hati+(2-lamda)hat...

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  3. The perpendicular distance between the line vecr = 2hati-2hatj+3hatk+l...

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  4. The vector equation of the line of intersection of the planes vecr.(2h...

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  5. A straight line vecr=veca+lambda vecb meets the plane vecr. vec n=0 at...

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  6. The equation of the plane passing through three non - collinear points...

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  7. The length of the perpendicular from the origin to the plane passing t...

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  8. The equation of the plane containing the line (x-x1)/l=(y-y1)/m=(z-...

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  9. Find the shortest distance between the following pairs of lines whose ...

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  10. If the lines (x-1)/(-3)=(y-2)/(2k)=(z-3)/2and (x-1)/(3k)=(y-1)/1=(z-6...

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  11. The direction ratios of a normal to the plane passing throuhg (0,0,1)...

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  12. A variable plane is at a distance, k from the origin and meets the coo...

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  13. Find the equation of the plane perpendicular to the line (x-1)/2=(y...

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  14. Find the equation of the plane through the points (2,2,1) and (9,3,6) ...

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  15. The equation of the plane containing the two lines (x-1)/2=(y+1)/(-1...

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  16. The direction ratios of the normal to the plane passing through the po...

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  17. The equation of a plane through the point (2, 3, 1) and (4, -5, 3) a...

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  18. The angle between the lines (x+4)/(1) = (y-3)/(2) = (z+2)/(3) and (x)/...

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  19. The equation of the plane which is perpendicular bisector of the line ...

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  20. If the position vectors of the point A and B are 3hat(i)+hat(j)+2hat(k...

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