Home
Class 12
MATHS
The equation of the plane which is perpe...

The equation of the plane which is perpendicular bisector of the line joining the points `A(1, 2, 3)` and `B(3, 4, 5)` is

A

`x+y+z=9`

B

`x+y+z=-9`

C

`2xx3y+4z=9`

D

`2x+3y+4z=-9`

Text Solution

AI Generated Solution

The correct Answer is:
To find the equation of the plane that is the perpendicular bisector of the line segment joining the points \( A(1, 2, 3) \) and \( B(3, 4, 5) \), we can follow these steps: ### Step 1: Find the Midpoint of the Line Segment AB The midpoint \( C \) of the line segment joining points \( A \) and \( B \) can be calculated using the midpoint formula: \[ C\left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}, \frac{z_1 + z_2}{2} \right) \] Substituting the coordinates of points \( A \) and \( B \): \[ C\left( \frac{1 + 3}{2}, \frac{2 + 4}{2}, \frac{3 + 5}{2} \right) = C\left( \frac{4}{2}, \frac{6}{2}, \frac{8}{2} \right) = C(2, 3, 4) \] ### Step 2: Find the Direction Vector AB The direction vector \( \overrightarrow{AB} \) can be found by subtracting the coordinates of point \( A \) from point \( B \): \[ \overrightarrow{AB} = B - A = (3 - 1, 4 - 2, 5 - 3) = (2, 2, 2) \] ### Step 3: Determine the Normal Vector The normal vector \( \mathbf{n} \) of the plane is the same as the direction vector \( \overrightarrow{AB} \): \[ \mathbf{n} = (2, 2, 2) \] ### Step 4: Use the Point-Normal Form of the Plane Equation The equation of a plane can be expressed in the point-normal form: \[ \mathbf{n} \cdot (\mathbf{r} - \mathbf{r_0}) = 0 \] Where \( \mathbf{r} = (x, y, z) \) is a general point on the plane, and \( \mathbf{r_0} = (2, 3, 4) \) is a point on the plane. Substituting the values: \[ (2, 2, 2) \cdot ((x, y, z) - (2, 3, 4)) = 0 \] This expands to: \[ (2, 2, 2) \cdot (x - 2, y - 3, z - 4) = 0 \] Calculating the dot product: \[ 2(x - 2) + 2(y - 3) + 2(z - 4) = 0 \] Simplifying: \[ 2x - 4 + 2y - 6 + 2z - 8 = 0 \] \[ 2x + 2y + 2z - 18 = 0 \] Dividing through by 2: \[ x + y + z = 9 \] ### Final Equation of the Plane Thus, the equation of the plane which is the perpendicular bisector of the line segment joining points \( A \) and \( B \) is: \[ x + y + z = 9 \]

To find the equation of the plane that is the perpendicular bisector of the line segment joining the points \( A(1, 2, 3) \) and \( B(3, 4, 5) \), we can follow these steps: ### Step 1: Find the Midpoint of the Line Segment AB The midpoint \( C \) of the line segment joining points \( A \) and \( B \) can be calculated using the midpoint formula: \[ C\left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}, \frac{z_1 + z_2}{2} \right) \] Substituting the coordinates of points \( A \) and \( B \): ...
Promotional Banner

Topper's Solved these Questions

  • PLANE AND STRAIGHT LINE IN SPACE

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|31 Videos
  • PLANE AND STRAIGHT LINE IN SPACE

    OBJECTIVE RD SHARMA ENGLISH|Exercise Section II - Assertion Reason Type|16 Videos
  • MISCELLANEOUS EQUATIONS AND INEQUATIONS

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|29 Videos
  • PROPERTIES OF TRIANGLES AND CIRCLES CONNECTED WITH THEM

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|55 Videos

Similar Questions

Explore conceptually related problems

Find the equation of the perpendicular bisector of the line joining the points (1,3) and (3,1).

Find the equation of the perpendicular bisector of the line joining the points (1,3) and (-2,6) .

Find the equation of the perpendicular bisector of the line segment joining the points A(2,3) and B(6,-5) .

Find the equation of the perpendicular bisector of the line segment joining the points A(2,3) and B(6,-5)dot

Find the equation of the perpendicular bisector of the line segment joining the points (1,1) and (2,3).

Find the equation of the perpendicular bisector of the line segment joining the points (1,0) and (3,5) .

Find the equation of the perpendicular bisector of the line segment joining the points (3,4) and (-1,2).

Find the equation of the perpendicular bisector of the line segment joining the points A(2,3)a n dB(6,-5)dot

The point which lies on the perpendicular bisector of the line segment joining the points A(-2,-5) and B (2,5) is

The perpendicular bisector of the line segment joining the points A(1,5) and B(4,6) cuts the Y-axis at

OBJECTIVE RD SHARMA ENGLISH-PLANE AND STRAIGHT LINE IN SPACE -Exercise
  1. Find the vector equation of the plane in which the lines vecr=hati+ha...

    Text Solution

    |

  2. The Cartesian equation of the plane vecr=(1+lamda-mu)hati+(2-lamda)hat...

    Text Solution

    |

  3. The perpendicular distance between the line vecr = 2hati-2hatj+3hatk+l...

    Text Solution

    |

  4. The vector equation of the line of intersection of the planes vecr.(2h...

    Text Solution

    |

  5. A straight line vecr=veca+lambda vecb meets the plane vecr. vec n=0 at...

    Text Solution

    |

  6. The equation of the plane passing through three non - collinear points...

    Text Solution

    |

  7. The length of the perpendicular from the origin to the plane passing t...

    Text Solution

    |

  8. The equation of the plane containing the line (x-x1)/l=(y-y1)/m=(z-...

    Text Solution

    |

  9. Find the shortest distance between the following pairs of lines whose ...

    Text Solution

    |

  10. If the lines (x-1)/(-3)=(y-2)/(2k)=(z-3)/2and (x-1)/(3k)=(y-1)/1=(z-6...

    Text Solution

    |

  11. The direction ratios of a normal to the plane passing throuhg (0,0,1)...

    Text Solution

    |

  12. A variable plane is at a distance, k from the origin and meets the coo...

    Text Solution

    |

  13. Find the equation of the plane perpendicular to the line (x-1)/2=(y...

    Text Solution

    |

  14. Find the equation of the plane through the points (2,2,1) and (9,3,6) ...

    Text Solution

    |

  15. The equation of the plane containing the two lines (x-1)/2=(y+1)/(-1...

    Text Solution

    |

  16. The direction ratios of the normal to the plane passing through the po...

    Text Solution

    |

  17. The equation of a plane through the point (2, 3, 1) and (4, -5, 3) a...

    Text Solution

    |

  18. The angle between the lines (x+4)/(1) = (y-3)/(2) = (z+2)/(3) and (x)/...

    Text Solution

    |

  19. The equation of the plane which is perpendicular bisector of the line ...

    Text Solution

    |

  20. If the position vectors of the point A and B are 3hat(i)+hat(j)+2hat(k...

    Text Solution

    |