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The value of lamda for which the lines (...

The value of `lamda` for which the lines `(x-1)/1=(y-2)/(lamda)=(z+1)/(-1)` and `(x+1)/(-lamda)=(y+1)/2=(z-2)/1` are perpendicular to each other is

A

0

B

1

C

-1

D

none of these

Text Solution

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The correct Answer is:
To find the value of \( \lambda \) for which the given lines are perpendicular, we can follow these steps: ### Step 1: Identify the direction ratios of the lines The given lines are represented in symmetric form. We can extract the direction ratios from these equations. For the first line: \[ \frac{x-1}{1} = \frac{y-2}{\lambda} = \frac{z+1}{-1} \] The direction ratios (denoted as \( V_1 \)) are: \[ 1, \lambda, -1 \] For the second line: \[ \frac{x+1}{-\lambda} = \frac{y+1}{2} = \frac{z-2}{1} \] The direction ratios (denoted as \( V_2 \)) are: \[ -\lambda, 2, 1 \] ### Step 2: Use the condition for perpendicularity Two lines are perpendicular if the dot product of their direction ratios is zero. Therefore, we need to calculate the dot product \( V_1 \cdot V_2 \): \[ V_1 \cdot V_2 = (1)(-\lambda) + (\lambda)(2) + (-1)(1) \] This simplifies to: \[ -\lambda + 2\lambda - 1 = 0 \] ### Step 3: Solve the equation Now, we simplify the equation: \[ \lambda - 1 = 0 \] Thus, we find: \[ \lambda = 1 \] ### Conclusion The value of \( \lambda \) for which the lines are perpendicular is: \[ \lambda = 1 \] ---

To find the value of \( \lambda \) for which the given lines are perpendicular, we can follow these steps: ### Step 1: Identify the direction ratios of the lines The given lines are represented in symmetric form. We can extract the direction ratios from these equations. For the first line: \[ \frac{x-1}{1} = \frac{y-2}{\lambda} = \frac{z+1}{-1} ...
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OBJECTIVE RD SHARMA ENGLISH-PLANE AND STRAIGHT LINE IN SPACE -Chapter Test
  1. The length of the perpendicular from the origin to the plane passing t...

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  2. The value of lamda for which the lines (x-1)/1=(y-2)/(lamda)=(z+1)/(-1...

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  3. The angle between the lines (x+4)/(1) = (y-3)/(2) = (z+2)/(3) and (x)/...

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  4. The direction cosines of the line 6x-2=3y+1=2z-2 are

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  5. A line passes through two points A(2,-3,-1) and B(8,-1,2). The coordin...

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  6. The position vector of a point at a distance of 3sqrt(11) units from h...

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  7. The line joining the points 6veca-4vecb+4vecc, -4vecc and the line joi...

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  8. The image (or reflection) of the point (1,2-1) in the plane vecr.(3hat...

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  9. The equation of the plane through the line of intersection of the plan...

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  10. Angle between the line vecr=(2hati-hatj+hatk)+lamda(-hati+hatj+hatk) a...

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  11. The line through hati+3hatj+2hatkandbot"to the line "vecr=(hati+2hatj-...

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  12. The distance of the point having position vector -hat(i) + 2hat(j) + 6...

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  13. The position vector of the point in which the line joining the points ...

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  14. The two lines vecr=veca+veclamda(vecbxxvecc) and vecr=vecb+mu(veccxxve...

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  15. Lines vecr = veca(1) + lambda vecb and vecr = veca(2) + svecb will lie...

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  16. Equation of a line passing through (-1,2,-3) and perpendicular to the ...

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  17. Find the Vector and Cartesian equation of line passing through (1, -2,...

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  18. The distance between the planes given by vecr.(hati+2hatj-2hatk)+5=0...

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  19. Find shortest distance between the line vecr = (5hati + 7hatj + 3ha...

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  20. Find the shortest distance between the lines vecr=(hatii+2hatj+hatk)+l...

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