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If |veca|=3,|vecb|= 5 and |vecc|=4 and v...

If `|veca|=3,|vecb|= 5 and |vecc|=4 and veca+ vecb + vecc =vec0` then the value of `( veca. vecb + vecb.vecc)` is equal tio

A

0

B

-25

C

25

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
we have,
` veca +vecb + vecc= vec0`
` Rightarrow ( veca + vecb + vecc) , vecb = vec0 .vecb` [ Taking dot product with ` vecb`]
` veca.vecb + vecb.vecb + vecc.vecb =0`
` Rightarrow veca. Vecb + |vecb|^(2) + vecb.vecc =0 Rightarrow veca. vecb + vecb.vecc=-25`
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