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Let veca, vecb and vecc be unit vectors ...

Let `veca, vecb and vecc` be unit vectors such that `veca.vecb=0 = veca.vecc`. It the angle between `vecb and vecc is pi/6` then find `veca`.

A

` +- 2(vecb xx vecc)`

B

` 2(vecb xx vecc)`

C

` +- 1/2(vecb xx vecc)`

D

` - 1/2 (vecb xx vecc)`

Text Solution

Verified by Experts

The correct Answer is:
A
we have ,
` veca.vecb= veca.vecc = vec0`
` Rightarrow veca bot vecb, veca bot vecc`
` Rightarrow veca || (vecb xx vecc)`
` Rightarrow veca = +- (vecb xx vecc)/(|vecb xx vecc|) =+- (|vecb xx vecc|)/(|vecb||vecc| sin pi/3) = +- 2 ( vecb xx vecc)`
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