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The solution of the differential equatio...

The solution of the differential equation `x^(3)(dy)/(dx)+4x^(2) tany=e^(x) secy` satisfying `y(1)=0`, is

A

`tany=(x-2)e^(x)logx`

B

`siny=e^(x)(x-1)x^(-4)`

C

`tany=(x-1)e^(x)x^(-3)`

D

`siny=e^(x)(x-1)x^(-3)`

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The correct Answer is:
To solve the given differential equation \[ x^3 \frac{dy}{dx} + 4x^2 \tan y = e^x \sec y \] with the initial condition \( y(1) = 0 \), we will follow these steps: ### Step 1: Rearranging the Equation First, we will divide the entire equation by \( x^3 \) to simplify it: \[ \frac{dy}{dx} + \frac{4}{x} \tan y = \frac{e^x \sec y}{x^3} \] ### Step 2: Multiplying by \( \cos y \) Next, we multiply through by \( \cos y \): \[ \cos y \frac{dy}{dx} + \frac{4}{x} \sin y = \frac{e^x}{x^3} \] ### Step 3: Rearranging for Integration Now, we can rearrange this equation for integration: \[ \cos y \frac{dy}{dx} = \frac{e^x}{x^3} - \frac{4}{x} \sin y \] ### Step 4: Multiplying by \( x^4 \) To facilitate integration, we multiply the entire equation by \( x^4 \): \[ x^4 \cos y \frac{dy}{dx} + 4x^3 \sin y = x e^x \] ### Step 5: Recognizing the Left Side as a Derivative The left-hand side can be recognized as the derivative of a product: \[ \frac{d}{dx}(x^4 \sin y) = x e^x \] ### Step 6: Integrating Both Sides Now we integrate both sides: \[ \int \frac{d}{dx}(x^4 \sin y) \, dx = \int x e^x \, dx \] The integral on the left gives us: \[ x^4 \sin y = \int x e^x \, dx \] Using integration by parts, we find: \[ \int x e^x \, dx = e^x (x - 1) + C \] Thus, we have: \[ x^4 \sin y = e^x (x - 1) + C \] ### Step 7: Solving for \( \sin y \) Now, we can express \( \sin y \): \[ \sin y = \frac{e^x (x - 1) + C}{x^4} \] ### Step 8: Applying the Initial Condition We know that \( y(1) = 0 \), which implies \( \sin(0) = 0 \). Substituting \( x = 1 \): \[ 0 = \frac{e^1 (1 - 1) + C}{1^4} \] This simplifies to: \[ 0 = C \] ### Step 9: Final Solution Substituting \( C = 0 \) back into the equation gives us: \[ \sin y = \frac{e^x (x - 1)}{x^4} \] ### Conclusion The solution to the differential equation is: \[ \sin y = \frac{e^x (x - 1)}{x^4} \]

To solve the given differential equation \[ x^3 \frac{dy}{dx} + 4x^2 \tan y = e^x \sec y \] with the initial condition \( y(1) = 0 \), we will follow these steps: ...
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OBJECTIVE RD SHARMA ENGLISH-DIFFERENTIAL EQUATIONS-Chapter Test
  1. The solution of the differential equation x^(3)(dy)/(dx)+4x^(2) tany=e...

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  2. (x^(2)+y ^(2)) dy = xydx. If y (x (o)) =e, y (1)=1, then the value of ...

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  3. The differential equation of the family of curves y^(2)=4xa(x+1), is

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  4. y=ae^(mx)+be^(-mx) satisfies which of the following differential equat...

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  5. The solution of the differential equation (dy)/(dx)=e^(y+x)+e^(y-x), i...

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  6. The differential equation of the family of curves y=e^(2x)(a cos x+b s...

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  7. The differential equation obtained on eliminating A and B from y=A c...

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  8. The solution of (dy)/(dx)=((y)/(x))^(1//3), is

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  9. The slope of the tangent at (x , y) to a curve passing through a po...

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  10. Solve Y-X(dy)/(dx)=a(y^(2)+(dy)/(dx))

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  11. The solution of the differential equation (x+2y^(2))(dy)/(dx)=y, is

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  12. The general solution of the differential equation (dy)/(dx)+sin((x+y)/...

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  13. The solution of (dy)/(dx)-y=1, y(0)=1 is given by

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  14. The number of solution of y'=(x+1)/(x-1),y(1)=2, is

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  15. What is the solution of y'=1+x+y^(2)+xy^(2),y(0)=0?

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  16. Solution of the differential equation x(dy)/(dx)=y+sqrt(x^(2)+y^(2)), ...

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  17. Integral curve satisfying Y'=(x^2 +y^2)/(x^2-y^2) y' (1) ne 1 has th...

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  18. The differential equation which represents the family of plane curves ...

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  19. A continuously differentiable function y=f(x) , x in ((-pi)/(2) ,(pi)/...

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  20. The solution of the differential equation (d^(2)y)/(dx^(2))=e^(-2x), i...

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  21. The order and degree of the differential equation (d^(2)y)/(dx^(2))=sq...

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