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Integral curve satisfying Y'=(x^2 +y^2)...

Integral curve satisfying ` Y'=(x^2 +y^2)/(x^2-y^2) y' (1) ne 1` has the slope at the point (1, 0) of the curve equal to:

A

`-(5)/(3)`

B

`-1`

C

1

D

`(5)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
We have,
`(dy)/(dx)=(x^(2)+y^(2))/(x^(2)-y^(2))`
`therefore" Slope of the tangent at (1, 0)"=((dy)/(dx))_("(1,0)")=(1+0)/(1-0)=1`
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