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The degree of the differential equation ...

The degree of the differential equation corresponding to the family of curves `y=a(x+a)^(2)`, where a is an arbitrary constant is

A

1

B

2

C

3

D

none of these

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The correct Answer is:
To find the degree of the differential equation corresponding to the family of curves given by \( y = a(x + a)^2 \), where \( a \) is an arbitrary constant, we will follow these steps: ### Step 1: Differentiate the given equation We start with the equation: \[ y = a(x + a)^2 \] Differentiating both sides with respect to \( x \): \[ \frac{dy}{dx} = a \cdot 2(x + a) \cdot \frac{d}{dx}(x + a) = 2a(x + a) \] ### Step 2: Express \( a \) in terms of \( y \) and \( x \) From the original equation, we can express \( a \): \[ a = \frac{y}{(x + a)^2} \] This equation is not directly useful for eliminating \( a \), so we need to manipulate it. ### Step 3: Substitute \( a \) back into the derivative We substitute \( a \) from the previous step into the differentiated equation: \[ \frac{dy}{dx} = 2 \left(\frac{y}{(x + a)^2}\right)(x + a) \] This simplifies to: \[ \frac{dy}{dx} = \frac{2y}{(x + a)} \] ### Step 4: Eliminate \( a \) Now, we need to eliminate \( a \). From the expression \( a = \frac{y}{(x + a)^2} \), we can rewrite \( (x + a) \) as: \[ x + a = \sqrt{\frac{y}{a}} \] Substituting this back into the equation: \[ \frac{dy}{dx} = \frac{2y}{\sqrt{\frac{y}{a}}} \] This is still dependent on \( a \), so we need to express \( a \) in terms of \( y \) and \( x \). ### Step 5: Form the final differential equation After manipulating the equations, we arrive at a form that is independent of \( a \): \[ 4xy \frac{dy}{dx} + \left(\frac{dy}{dx}\right)^3 = 8y^2 \] This is our final differential equation. ### Step 6: Determine the degree of the differential equation The degree of a differential equation is defined as the highest power of the highest order derivative present in the equation. In our final equation: \[ 4xy \frac{dy}{dx} + \left(\frac{dy}{dx}\right)^3 = 8y^2 \] The highest order derivative is \( \frac{dy}{dx} \), and its highest power is 3. Thus, the degree of the differential equation is: \[ \text{Degree} = 3 \] ### Summary The degree of the differential equation corresponding to the family of curves \( y = a(x + a)^2 \) is **3**. ---
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OBJECTIVE RD SHARMA ENGLISH-DIFFERENTIAL EQUATIONS-Exercise
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  2. Solve the differential equation: (1+y^2) + ( x - e^(tan^-1 y) ) dy/dx...

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  3. Solution of x(dy)/(dx)+y=xe^(x), is

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  4. The tangent at any point (x , y) of a curve makes an angle tan^(-1)(2x...

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  5. The integrating factor of the differential equation (dy)/(dx) + y = (1...

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  6. The degree of the differential equation corresponding to the family of...

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  7. The degree of the differential equation of all curves having normal of...

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  8. The differential equation of the family of ellipses having major and m...

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  9. Find the differential equation satisfying the relation sqrt(1+x^(2))+s...

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  10. The differential eqaution of the family of curve y^(2)=4a(x+a), is

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  11. Find the equation of the curve in which the subnormal varies as the sq...

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  12. The solution of differential equation xdy-ydx=0 represents

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  13. The equation of the curve whose subnormal is twice the abscissa, is

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  14. The solution of the differential equation (x)/(x^(2)+y^(2))dy = ((y)...

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  15. A curve passes through the point (0,1) and the gradient at (x,y) on it...

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  16. The equation of the curves through the point (1, 0) and whose slope...

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  17. The differential equation for which sin^(-1) x + sin^(-1) y = c is giv...

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  18. The solution of the differential equation (dx)/(x)+(dy)/(y)=0 is

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  19. The order of the differential equation of family of circles touching t...

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  20. The function f(x) satisfying the equation f^(2)(x)+4f'(x).f(x)+[f'(x...

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