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If |veca|=5, |vecb|=3, |vecc|=4 and veca...

If `|veca|=5, |vecb|=3, |vecc|=4` and `veca` is perpendicular to `vecb` and `vecc` such that angle between `vecb` and `vecc` is `(5pi)/6`, then the volume of the parallelopiped having `veca, vecb` and `vecc` as three coterminous edges is

A

30 cubit units

B

60 cubic units

C

20 cubic units

D

none of these

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The correct Answer is:
To find the volume of the parallelepiped formed by the vectors \(\vec{a}\), \(\vec{b}\), and \(\vec{c}\), we can use the formula for the volume \(V\) given by the scalar triple product: \[ V = |\vec{a} \cdot (\vec{b} \times \vec{c})| \] ### Step 1: Identify the magnitudes and relationships of the vectors We are given: - \(|\vec{a}| = 5\) - \(|\vec{b}| = 3\) - \(|\vec{c}| = 4\) - \(\vec{a}\) is perpendicular to both \(\vec{b}\) and \(\vec{c}\). Since \(\vec{a}\) is perpendicular to \(\vec{b}\) and \(\vec{c}\), we have: \[ \vec{a} \cdot \vec{b} = 0 \quad \text{and} \quad \vec{a} \cdot \vec{c} = 0 \] ### Step 2: Find the angle between \(\vec{b}\) and \(\vec{c}\) The angle between \(\vec{b}\) and \(\vec{c}\) is given as: \[ \theta = \frac{5\pi}{6} \] ### Step 3: Calculate the magnitude of \(\vec{b} \times \vec{c}\) The magnitude of the cross product \(|\vec{b} \times \vec{c}|\) can be calculated using the formula: \[ |\vec{b} \times \vec{c}| = |\vec{b}| |\vec{c}| \sin(\theta) \] Substituting the known values: \[ |\vec{b} \times \vec{c}| = 3 \times 4 \times \sin\left(\frac{5\pi}{6}\right) \] ### Step 4: Calculate \(\sin\left(\frac{5\pi}{6}\right)\) Using the sine function: \[ \sin\left(\frac{5\pi}{6}\right) = \sin\left(\pi - \frac{\pi}{6}\right) = \sin\left(\frac{\pi}{6}\right) = \frac{1}{2} \] ### Step 5: Substitute back to find \(|\vec{b} \times \vec{c}|\) Now substituting this back: \[ |\vec{b} \times \vec{c}| = 3 \times 4 \times \frac{1}{2} = 6 \] ### Step 6: Calculate the volume of the parallelepiped Now we can find the volume using the scalar triple product: \[ V = |\vec{a}| \cdot |\vec{b} \times \vec{c}| = 5 \cdot 6 = 30 \] ### Final Answer Thus, the volume of the parallelepiped is: \[ \boxed{30} \text{ cubic units} \]

To find the volume of the parallelepiped formed by the vectors \(\vec{a}\), \(\vec{b}\), and \(\vec{c}\), we can use the formula for the volume \(V\) given by the scalar triple product: \[ V = |\vec{a} \cdot (\vec{b} \times \vec{c})| \] ### Step 1: Identify the magnitudes and relationships of the vectors We are given: ...
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OBJECTIVE RD SHARMA ENGLISH-SCALAR AND VECTOR PRODUCTS OF THREE VECTORS -Section I - Solved Mcqs
  1. If veca bot vecb then vector vecv in terms of veca and vecb satisfying...

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  2. Find the value of a so that the volume of the parallelopiped formed b...

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  3. let veca , vecb and vecc be three vectors having magnitudes 1, 1 and 2...

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  4. If vecA , vecB and vecC are vectors such that |vecB| = |vecC| prove th...

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  5. If the magnitude of the moment about the pont hatj+hatk of a force hat...

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  6. If the volume of parallelopiped formed by the vectors a,b,c as three c...

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  7. If |veca|=5, |vecb|=3, |vecc|=4 and veca is perpendicular to vecb and ...

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  8. If the vectors veca, vecb, vecc and vecd are coplanar vectors, then (...

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  9. Prove that (veca.(vecbxxhati))hati+(veca.(vecbxxhatj))hatj+ (veca.(vec...

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  10. The unit vector which is orhtogonal to the vector 3hati+2hatj+6hatk an...

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  11. Let veca, vecb and vecc be non-zero vectors such that (veca xx vecb) x...

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  12. vecp, vecq and vecr are three mutually prependicular vectors of the sa...

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  13. If veca and vecb are vectors in space given by veca= (hati-2hatj)/sqrt...

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  14. Two adjacent sides of a parallelogram A B C D are given by vec A B=...

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  15. Let a=hat(j)-hat(k) and b=hat(i)-hat(j)-hat(k). Then, the vector v sat...

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  16. The vector(s) which is /are coplanar with vectors hati +hatj + 2hatk a...

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  17. Let veca=-hati-hatk,vecb =-hati + hatj and vecc = i + 2hatj + 3hatk be...

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  18. veca =1/sqrt(10)(3hati + hatk) and vecb =1/7(2hati +3hatj-6hatk), then...

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  19. If veca=hati-2hatj+3hatk, vecb=2hati+3hatj-hatk and vecc=rhati+hatj+(2...

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  20. If veca, vecb are non zero vectors, then ((vecaxxvecb)xxveca).((vecbxx...

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