The vlaue of `tan^(-1)1/2+tan^(-1)1/3` is

Options

A. 0
B. `(pi)/(3)`
C. `(pi)/(6)`
D. `(pi)/(4)`

Explanation

To solve the problem \( \tan^{-1}\left(\frac{1}{2}\right) + \tan^{-1}\left(\frac{1}{3}\right) \), we can use the formula for the sum of inverse tangents:

\[ \tan^{-1}(x) + \tan^{-1}(y) = \tan^{-1}\left(\frac{x+y}{1-xy}\right) \]

provided that \( xy < 1 \).

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