If `-1lexle0` then `tan{1/2sin^(-1)((2x)/(1+x^(2)))+1/2cos^(-1)((1-x^(2))/(1+x^(2)))}` is equal to

Options

A. `(2x)/(1-x^(2))`
B. 0
C. `(2x)/(1+x^(2))`
D. x

Explanation

To solve the problem, we need to evaluate the expression:

\[ \tan\left(\frac{1}{2}\sin^{-1}\left(\frac{2x}{1+x^2}\right) + \frac{1}{2}\cos^{-1}\left(\frac{1-x^2}{1+x^2}\right)\right) \]

given that \( -1 \leq x \leq 0 \).

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