In a `DeltaABC`, if a = 4, b = 5 , c = 6 then angle C is equal to

Options

A. A
B. `1/2A`
C. 2A
D. 3A

Explanation

To find angle C in triangle ABC, where the sides are given as \( a = 4 \), \( b = 5 \), and \( c = 6 \), we can use the cosine rule. The cosine rule states that:

\[ \cos C = \frac{a^2 + b^2 - c^2}{2ab} \]

### Step-by-Step Solution:

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