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In a DeltaABC,(a+c)/(a-c)tan(B/2) is eq...

In a `DeltaABC,(a+c)/(a-c)tan(B/2)` is equal to

A

`tan(B/2+C)`

B

`tan(B+C/2)`

C

`cot(B/2+C)`

D

none of these

Text Solution

AI Generated Solution

To solve the problem, we need to evaluate the expression \(\frac{A + C}{A - C} \tan\left(\frac{B}{2}\right)\) in triangle \(ABC\). ### Step-by-Step Solution: 1. **Use the Sine Rule**: The sine rule states that: \[ \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} = K ...
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