If the lengths of the sides of a triangle are a - b , a + b and `sqrt(3a^(2)+b^(2)),(a,bgt,0)`, then the largest angle of the triangle , is

Options

A. `(2pi)/3`
B. `(3pi)/4`
C. `(pi)/2`
D. `(7pi)/8`

Explanation

To solve the problem step by step, we will determine the largest angle of the triangle with sides \( a - b \), \( a + b \), and \( \sqrt{3a^2 + b^2} \).

### Step 1: Identify the sides of the triangle
Let:
- \( x = a - b \)
- \( y = a + b \)
- \( z = \sqrt{3a^2 + b^2} \)

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