If in a `triangle ABC` sin A =`4/5` and sin B =`12/13`, then sin C =

Options

A. `33/65`
B. `56/65`
C. `33/56`
D. none of these

Explanation

To find the value of sin C in triangle ABC where sin A = 4/5 and sin B = 12/13, we can follow these steps:

### Step-by-Step Solution:

1. **Calculate cos A:**
\[ \cos A = \sqrt{1 - \sin^2 A} = \sqrt{1 - \left(\frac{4}{5}\right)^2} = \sqrt{1 - \frac{16}{25}} = \sqrt{\frac{9}{25}} = \frac{3}{5} \]
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