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In a !ABC , 2r = r(1) and A=30 , then c...

In a `!ABC` , 2r = `r_(1)` and A=30 , then cos `(B - C)/2` is equal to

A

`(3sqrt3)/(2sqrt2)`

B

`(3(sqrt3-1))/(2sqrt2)`

C

`(3(sqrt3-1))/(2sqrt3)`

D

none of these

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To solve the problem, we need to find the value of \( \cos \left( \frac{B - C}{2} \right) \) given that \( 2r = r_1 \) and \( A = 30^\circ \). ### Step-by-Step Solution: 1. **Understanding the relationship between r and r1**: - We know that \( r \) is the inradius and \( r_1 \) is the exradius opposite to angle A. The relationship given is \( 2r = r_1 \). 2. **Using the formula for inradius and exradius**: ...
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