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In a `!ABC` , there is a point `D` on the side BC such that `(BD)/(DC)` =`1/3`.If `angleB=pi/3,angleC=pi/4` and `sinangle(CAD)=lamdasinangleBAD` then `lamda` is equal to

A

`1/(sqrt6)`

B

`sqrt6`

C

`1/(sqrt3)`

D

`sqrt3`

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To solve the problem step by step, we will use the properties of triangles and the sine rule. ### Step-by-Step Solution: 1. **Identify the Given Information:** - Triangle \( ABC \) with point \( D \) on side \( BC \). - The ratio \( \frac{BD}{DC} = \frac{1}{3} \). - Angles: \( \angle B = \frac{\pi}{3} \) and \( \angle C = \frac{\pi}{4} \). ...
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