If the area`(!)` and an angle`(theta)` of a triangle are given , when the side opposite to the given angle is minimum , then the length of the remaining two sides are

Options

A. `sqrt((2!)/(sintheta)),sqrt((3!)/(sintheta))`
B. `sqrt((2!)/(sintheta)),sqrt((2!)/(sintheta))`
C. `sqrt((4!)/(sintheta)),sqrt((4!)/(sintheta))`
D. `sqrt((6!)/(sintheta)),sqrt((6!)/(sintheta))`

Explanation

To solve the problem, we need to find the lengths of the remaining two sides of a triangle when the area and an angle (θ) are given, and the side opposite to the given angle is minimized.

### Step-by-Step Solution:

1. **Understanding the Triangle**:
Let triangle ABC have sides A, B, and C, where C is the side opposite to angle θ. We are given the area of the triangle and the angle θ.

2. **Area of the Triangle**:
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