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In !ABC , x , y , and z are the distance...

In `!ABC` , x , y , and z are the distance of incentre from angular points A , B ,and C respectively . If`(xyz)/(abc)=(lamdar)/s` , then `lamda`=

A

1

B

2

C

3

D

none of these

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To solve the problem, we need to find the value of \(\lambda\) given the relationship: \[ \frac{xyz}{abc} = \frac{\lambda R}{s} \] where \(x\), \(y\), and \(z\) are the distances from the incenter \(I\) to the vertices \(A\), \(B\), and \(C\) of triangle \(ABC\), \(R\) is the circumradius, \(s\) is the semi-perimeter, and \(a\), \(b\), and \(c\) are the lengths of the sides opposite to vertices \(A\), \(B\), and \(C\) respectively. ...
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OBJECTIVE RD SHARMA ENGLISH-PROPERTIES OF TRIANGLES AND CIRCLES CONNECTED WITH THEM-Section I - Solved Mcqs
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