In any `!ABC `, sin `A/2` is

Options

A. less than `(b+c)/a`
B. less than or equal to `a/(b+c)`
C. greater than `(2a)/(a+b+c)`
D. none of these

Explanation

To find the value of \( \sin \frac{A}{2} \) in any triangle \( ABC \), we can use the following steps:

### Step 1: Use the Sine Rule
We know from the sine rule that:
\[ \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \]
This implies:
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