In a `triangle ABC` if sin A cos B = `1/4` and 3 tan A = tan B , then the triangle is

Options

A. right angled at A
B. right angled at B
C. right angled at C
D. not right angled

Explanation

To solve the problem step by step, we will use the given information about triangle \( ABC \) and the relationships between the angles.

### Step 1: Write down the given information
We are given:
1. \( \sin A \cos B = \frac{1}{4} \)
2. \( 3 \tan A = \tan B \)

### Step 2: Express \( \tan A \) and \( \tan B \) in terms of sine and cosine
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