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ABC is a triangle. D is the middle point...

ABC is a triangle. D is the middle point of BC. If AD is perpendicular to AC, The value of cos A cos C , is

A

`(3(c^(2)-a^(2))/(ac)`

B

`(a^(2)-c^(2))/(2ac)`

C

`(2(c^(2)-a^(2))/(3ac)`

D

none of these

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AI Generated Solution

To solve the problem, we need to find the value of \( \cos A \cos C \) given that \( D \) is the midpoint of \( BC \) and \( AD \) is perpendicular to \( AC \). ### Step-by-Step Solution: 1. **Draw Triangle ABC**: - Let \( A \), \( B \), and \( C \) be the vertices of the triangle. - Let \( D \) be the midpoint of side \( BC \). ...
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