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Sides a , b , c of `!ABC` are in A.P. and `costheta_(1)=a/(b+c)costheta_(2)=b/(a+c),costheta_(3)=c/(a+b)` , then `tan^(2)(theta_(1))/2+tan^(2)(theta_(3))/2`=

A

`2//3`

B

1

C

`sqrt5//3`

D

none of these

Text Solution

AI Generated Solution

To solve the problem step by step, we will analyze the given conditions and derive the required expression. ### Step 1: Understand the given conditions We know that the sides \( a, b, c \) of triangle \( ABC \) are in Arithmetic Progression (A.P.). This means we can express the sides as: - \( a = b - d \) - \( b = b \) - \( c = b + d \) ...
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