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If in a triangle ABC ,a sin A=b sin B, t...

If in a `triangle ABC` ,a sin A=b sin B, then the triangle, is

A

right angled

B

equilaterial

C

isosceles

D

none of these

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The correct Answer is:
To solve the problem, we need to analyze the given condition in triangle ABC, which states that \( a \sin A = b \sin B \). We will derive the conclusion step by step. ### Step-by-Step Solution: 1. **Given Condition**: We start with the equation given in the problem: \[ a \sin A = b \sin B \] 2. **Using the Sine Rule**: According to the sine rule, we have: \[ \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} = K \] where \( K \) is a constant. 3. **Expressing Sine Values**: From the sine rule, we can express \( \sin A \) and \( \sin B \) in terms of \( K \): \[ \sin A = \frac{a}{K} \quad \text{and} \quad \sin B = \frac{b}{K} \] 4. **Substituting into the Given Condition**: Substitute these expressions into the original equation: \[ a \left(\frac{a}{K}\right) = b \left(\frac{b}{K}\right) \] This simplifies to: \[ \frac{a^2}{K} = \frac{b^2}{K} \] 5. **Canceling K**: Since \( K \) is a constant and cannot be zero, we can cancel \( K \) from both sides: \[ a^2 = b^2 \] 6. **Taking the Square Root**: Taking the square root of both sides gives us: \[ a = \pm b \] Since side lengths cannot be negative, we discard the negative solution: \[ a = b \] 7. **Conclusion**: If \( a = b \), it means that triangle ABC has two equal sides. Therefore, triangle ABC is an **isosceles triangle**. ### Final Answer: The triangle is **isosceles**. ---
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