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If r is the radius of inscribed circle o...

If r is the radius of inscribed circle of a regular polygon of n-sides ,then r is equal to

A

`a/2cot(pi/(2n))`

B

`a/2cot(pi/(n))`

C

`a/2tan(pi/(n))`

D

`a/2cos(pi/(n))`

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The correct Answer is:
To find the radius \( r \) of the inscribed circle of a regular polygon with \( n \) sides, we can derive the formula step by step as follows: ### Step 1: Understand the Regular Polygon A regular polygon with \( n \) sides has all sides and angles equal. The inscribed circle (incircle) touches each side of the polygon at its midpoint. ### Step 2: Draw the Polygon and the Incircle Draw a regular polygon with \( n \) sides. Inscribe a circle within this polygon. Label the center of the circle as \( O \) and the points where the circle touches the sides as \( A, B, C, \ldots \). ### Step 3: Identify Triangle and Angles Consider one of the triangles formed by the center \( O \), a vertex \( A \), and the midpoint of the side opposite to \( A \), which we can denote as \( D \). The angle \( \angle AOD \) is the central angle corresponding to the side \( AB \). ### Step 4: Calculate the Central Angle The total angle around point \( O \) is \( 360^\circ \) or \( 2\pi \) radians. Since there are \( n \) sides, the central angle \( \angle AOB \) for each side is: \[ \text{Central angle} = \frac{360^\circ}{n} = \frac{2\pi}{n} \] Thus, the angle \( \angle AOD \) (which is half of the central angle) is: \[ \angle AOD = \frac{1}{2} \cdot \frac{2\pi}{n} = \frac{\pi}{n} \] ### Step 5: Use Trigonometric Ratios In triangle \( AOD \), we can use the cotangent function. The radius \( r \) (which is \( OD \)) is the adjacent side to angle \( AOD \), and the length of half the side \( AB \) (which we denote as \( \frac{a}{2} \), where \( a \) is the length of one side of the polygon) is the opposite side. Using the cotangent function: \[ \cot\left(\frac{\pi}{n}\right) = \frac{\text{adjacent}}{\text{opposite}} = \frac{r}{\frac{a}{2}} \] ### Step 6: Solve for \( r \) Rearranging the equation gives: \[ r = \frac{a}{2} \cot\left(\frac{\pi}{n}\right) \] ### Conclusion Thus, the radius \( r \) of the inscribed circle of a regular polygon with \( n \) sides is: \[ r = \frac{a}{2} \cot\left(\frac{\pi}{n}\right) \]
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OBJECTIVE RD SHARMA ENGLISH-PROPERTIES OF TRIANGLES AND CIRCLES CONNECTED WITH THEM-Exercise
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  4. The area of a regular polygon of n sides is (where r is inradius, R is...

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  9. If A(1),A(2),A(3) denote respectively the areas of an inscribed polygo...

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