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If r,r(1) ,r(2), r(3) have their usual m...

If `r,r_(1) ,r_(2), r_(3)` have their usual meanings , the value of `1/(r_(1))+1/(r_(2))+1/(r_(3))`, is

A

1

B

0

C

`1/r`

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the given expressions and derive the required value systematically. ### Step-by-Step Solution: 1. **Understanding the Variables**: We have \( r, r_1, r_2, r_3 \) where: - \( r_1 = \frac{\Delta}{s - a} \) - \( r_2 = \frac{\Delta}{s - b} \) - \( r_3 = \frac{\Delta}{s - c} \) Here, \( \Delta \) is the area of the triangle, and \( s \) is the semi-perimeter given by \( s = \frac{a + b + c}{2} \). **Hint**: Identify the meanings of \( r, r_1, r_2, r_3 \) in the context of triangle geometry. 2. **Setting Up the Expression**: We need to find the value of: \[ \frac{1}{r_1} + \frac{1}{r_2} + \frac{1}{r_3} \] 3. **Substituting the Values**: Substitute the values of \( r_1, r_2, r_3 \): \[ \frac{1}{r_1} = \frac{s - a}{\Delta}, \quad \frac{1}{r_2} = \frac{s - b}{\Delta}, \quad \frac{1}{r_3} = \frac{s - c}{\Delta} \] Therefore, we can write: \[ \frac{1}{r_1} + \frac{1}{r_2} + \frac{1}{r_3} = \frac{s - a}{\Delta} + \frac{s - b}{\Delta} + \frac{s - c}{\Delta} \] **Hint**: Substitute the expressions for \( r_1, r_2, r_3 \) into the equation. 4. **Combining the Fractions**: Since all terms have a common denominator \( \Delta \), we can combine them: \[ \frac{(s - a) + (s - b) + (s - c)}{\Delta} \] 5. **Simplifying the Numerator**: Simplifying the numerator: \[ (s - a) + (s - b) + (s - c) = 3s - (a + b + c) \] Since \( a + b + c = 2s \), we have: \[ 3s - (2s) = s \] **Hint**: Use the relationship \( a + b + c = 2s \) to simplify the numerator. 6. **Final Expression**: Now substituting back, we get: \[ \frac{s}{\Delta} \] 7. **Relating to \( r \)**: We know that \( r = \frac{\Delta}{s} \), hence: \[ \frac{s}{\Delta} = \frac{1}{r} \] 8. **Conclusion**: Therefore, we conclude that: \[ \frac{1}{r_1} + \frac{1}{r_2} + \frac{1}{r_3} = \frac{1}{r} \] Thus, the final answer is: \[ \frac{1}{r} \] ### Final Answer: \[ \frac{1}{r} \]
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