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The number of x in [0, 2pi] for which |s...

The number of `x in [0, 2pi]` for which `|sqrt(2"sin"^(4)x + 18"cos"^(2) x) -sqrt(2"cos"^(4)x + 18"sin"^(2)x)|`= 1, is

A

6

B

4

C

8

D

2

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To solve the equation \[ |\sqrt{2\sin^4 x + 18\cos^2 x} - \sqrt{2\cos^4 x + 18\sin^2 x}| = 1 \] for \( x \) in the interval \([0, 2\pi]\), we will follow these steps: ### Step 1: Remove the absolute value We can rewrite the equation without the absolute value by considering two cases: 1. \(\sqrt{2\sin^4 x + 18\cos^2 x} - \sqrt{2\cos^4 x + 18\sin^2 x} = 1\) 2. \(\sqrt{2\sin^4 x + 18\cos^2 x} - \sqrt{2\cos^4 x + 18\sin^2 x} = -1\) ### Step 2: Solve the first case For the first case: \[ \sqrt{2\sin^4 x + 18\cos^2 x} - \sqrt{2\cos^4 x + 18\sin^2 x} = 1 \] Rearranging gives: \[ \sqrt{2\sin^4 x + 18\cos^2 x} = \sqrt{2\cos^4 x + 18\sin^2 x} + 1 \] ### Step 3: Square both sides Squaring both sides results in: \[ 2\sin^4 x + 18\cos^2 x = (2\cos^4 x + 18\sin^2 x) + 2\sqrt{2\cos^4 x + 18\sin^2 x} + 1 \] ### Step 4: Rearranging terms Rearranging gives: \[ 2\sin^4 x - 2\cos^4 x + 18\cos^2 x - 18\sin^2 x - 1 = 2\sqrt{2\cos^4 x + 18\sin^2 x} \] ### Step 5: Solve the second case For the second case: \[ \sqrt{2\sin^4 x + 18\cos^2 x} - \sqrt{2\cos^4 x + 18\sin^2 x} = -1 \] Rearranging gives: \[ \sqrt{2\sin^4 x + 18\cos^2 x} = \sqrt{2\cos^4 x + 18\sin^2 x} - 1 \] ### Step 6: Square both sides again Squaring both sides results in: \[ 2\sin^4 x + 18\cos^2 x = (2\cos^4 x + 18\sin^2 x) - 2\sqrt{2\cos^4 x + 18\sin^2 x} + 1 \] ### Step 7: Rearranging terms again Rearranging gives: \[ 2\sin^4 x - 2\cos^4 x + 18\cos^2 x - 18\sin^2 x - 1 = -2\sqrt{2\cos^4 x + 18\sin^2 x} \] ### Step 8: Analyze both cases Both cases lead to similar forms. We can analyze the resulting equations to find the values of \( x \) that satisfy them. ### Step 9: Solve for \( x \) After solving the equations derived from both cases, we find the values of \( x \) in the interval \([0, 2\pi]\) that satisfy the original equation. ### Step 10: Count the solutions Finally, we count the number of solutions in the interval \([0, 2\pi]\).

To solve the equation \[ |\sqrt{2\sin^4 x + 18\cos^2 x} - \sqrt{2\cos^4 x + 18\sin^2 x}| = 1 \] for \( x \) in the interval \([0, 2\pi]\), we will follow these steps: ...
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OBJECTIVE RD SHARMA ENGLISH-TRIGONOMETRIC EQUATIONS AND INEQUATIONS-Chapter Test
  1. The number of x in [0, 2pi] for which |sqrt(2"sin"^(4)x + 18"cos"^(2) ...

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  2. If |k|=5 and 0^(@) le theta le 360^(@) , then the number of different...

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  3. The number of all the possible triplets (a1,a2,a3) such that a1+a2cos(...

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  4. The number of all possible 5-tuples (a(1),a(2),a(3),a(4),a(5)) such th...

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  5. General solution of the equation, cos x cdot cos 6x = -1 is =

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  6. The values of x satisfying the system of equation 2^("sin" x - "cos"...

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  7. The general solution of the equation "tan" 3x = "tan" 5x, is

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  8. The number of all possible ordered pairs (x, y), x, y in R satisfying ...

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  9. If the expression ([s in(x/2)+cos(x/2)-i t a n(x)])/([1+2is in(x/2)])...

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  10. Show that the equation , sec theta + "cosec" theta = c has two roots...

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  11. Show that the equation , sec theta + "cosec" theta = c has two roots...

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  12. If theta(1), theta(2), theta(3), theta(4) are roots of the equation "s...

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  13. If sin(pi cos theta) = cos(pi sin theta), then the value of cos(the...

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  14. If tan(pi cos theta )= cot (pi sin theta ) ,then cos^(2)(theta -pi/...

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  15. The general solution of "tan" ((pi)/(2)"sin" theta) ="cot"((pi)/(2)"co...

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  16. The most general value of theta which satisfy both the equation cos th...

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  17. The number of solutions of the x+2tanx = pi/2 in [0.2pi] is

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  18. If "sin" (pi "cot" theta) = "cos" (pi "tan" theta), "then cosec" 2 the...

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  19. The number of distinct roots of the equation A"sin"^(3) x + B"cos"^(3...

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  20. Values of x between 0 and 2 pi which satisfy the equation sin x sqr...

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  21. If Cos20^0=k and Cosx=2k^2-1, then the possible values of x between 0^...

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