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The angle of elevation of the top of an incomplete vertical pillar at a horizontal distance of 50 m from its base is `45^@`. If the angle of elevation of the top of the complete pillar the same point is to be `60^@`,then the height of the incomplete pillar is to be increased by

A

`50sqrt2`m

B

100 m

C

`100 (sqrt3-1)m`

D

`100(sqrt3+1)`m

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To solve the problem step by step, we will use the concepts of trigonometry, particularly the tangent function, to find the heights of the incomplete and complete pillars. ### Step-by-Step Solution: 1. **Understanding the Problem**: - We have an incomplete vertical pillar and a complete vertical pillar. - The horizontal distance from the observer to the base of the pillar is 50 m. - The angle of elevation to the top of the incomplete pillar is \(45^\circ\). - The angle of elevation to the top of the complete pillar is \(60^\circ\). 2. **Finding the Height of the Incomplete Pillar**: - Let the height of the incomplete pillar be \(h\). - Using the tangent of the angle of elevation: \[ \tan(45^\circ) = \frac{h}{50} \] - We know that \(\tan(45^\circ) = 1\), so: \[ 1 = \frac{h}{50} \] - Thus, solving for \(h\): \[ h = 50 \text{ m} \] 3. **Finding the Height of the Complete Pillar**: - Let the height of the complete pillar be \(H\). - Using the tangent of the angle of elevation: \[ \tan(60^\circ) = \frac{H}{50} \] - We know that \(\tan(60^\circ) = \sqrt{3}\), so: \[ \sqrt{3} = \frac{H}{50} \] - Thus, solving for \(H\): \[ H = 50\sqrt{3} \text{ m} \] 4. **Calculating the Increase in Height**: - The increase in height required to complete the pillar is given by: \[ \Delta H = H - h \] - Substituting the values we found: \[ \Delta H = 50\sqrt{3} - 50 \] - Factoring out 50: \[ \Delta H = 50(\sqrt{3} - 1) \] 5. **Final Result**: - The height of the incomplete pillar needs to be increased by: \[ \Delta H = 50(\sqrt{3} - 1) \text{ m} \]
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OBJECTIVE RD SHARMA ENGLISH-HEIGHTS AND DISTANCES-Exercise
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