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The angle of elevation of the top of a t...

The angle of elevation of the top of a tower standing on a horizontal plane from a point `A` is `alpha` . After walking a distance d towards the foot of the tower the angle of elevation is found to be `beta` . The height of the tower is `d/(cotalpha+cotbeta)` (b) `d/(cotalpha-cotbeta)` `d/(tanbeta-t a nalpha)` (d) `d/(tanbeta+tanalpha)`

A

`(a sin alpha sin beta)/(sin (beta-alpha ))`

B

`(a sin alpha sin beta)/(sin (alpha -beta))`

C

`(a sin (beta-alpha ))/(sin alpha sin beta)`

D

`(a sin (alpha - beta))/(sin alpha sin beta) `

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The correct Answer is:
A
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OBJECTIVE RD SHARMA ENGLISH-HEIGHTS AND DISTANCES-Exercise
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