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From the top of a cliff 300 metres high,...

From the top of a cliff 300 metres high, the top of a tower was observed at an angle of depression `30^@` and from the foot of the tower the top of the cliff was observed at an angle of elevation `45^@`, The height of the tower is

A

`50(3-sqrt3)m`

B

`200(3-sqrt3)` m

C

`100(3-sqrt3)m`

D

none of these

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The correct Answer is:
To solve the problem step by step, we will use trigonometric ratios and the information given in the question. ### Step 1: Understand the Problem and Draw a Diagram We have a cliff of height 300 meters and a tower. From the top of the cliff, the angle of depression to the top of the tower is 30 degrees. From the foot of the tower, the angle of elevation to the top of the cliff is 45 degrees. We need to find the height of the tower. ### Step 2: Label the Diagram Let's label the points: - A: Top of the cliff - B: Foot of the cliff - C: Top of the tower - D: Foot of the tower Given: - Height of the cliff (AB) = 300 meters - Angle of depression from A to C = 30 degrees - Angle of elevation from D to A = 45 degrees ### Step 3: Use the Angle of Elevation to Find Distance BD From point D (foot of the tower), we can use the angle of elevation to find the horizontal distance (BD) from the foot of the cliff to the foot of the tower. Using the tangent function: \[ \tan(45^\circ) = \frac{AB}{BD} \] Since \(\tan(45^\circ) = 1\): \[ 1 = \frac{300}{BD} \implies BD = 300 \text{ meters} \] ### Step 4: Use the Angle of Depression to Find Height of Tower (DC) Now, we will use the angle of depression from A to C (the top of the tower). The angle of depression of 30 degrees corresponds to the angle of elevation from C to A. Using the tangent function: \[ \tan(30^\circ) = \frac{AB - DC}{BD} \] Where \(DC\) is the height of the tower. We know that \(\tan(30^\circ) = \frac{1}{\sqrt{3}}\): \[ \frac{1}{\sqrt{3}} = \frac{300 - DC}{300} \] ### Step 5: Solve for DC Cross-multiplying gives: \[ 300 = (300 - DC) \sqrt{3} \] Expanding: \[ 300 = 300\sqrt{3} - DC\sqrt{3} \] Rearranging gives: \[ DC\sqrt{3} = 300\sqrt{3} - 300 \] \[ DC = \frac{300(\sqrt{3} - 1)}{\sqrt{3}} \] ### Step 6: Simplify DC To simplify, we can multiply the numerator and denominator by \(\sqrt{3}\): \[ DC = 300 \left(1 - \frac{1}{\sqrt{3}}\right) = 300 \left(1 - \frac{\sqrt{3}}{3}\right) = 300 \left(\frac{3 - \sqrt{3}}{3}\right) = 100(3 - \sqrt{3}) \] ### Final Answer The height of the tower is: \[ \text{Height of the tower (DC)} = 100(3 - \sqrt{3}) \text{ meters} \]
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OBJECTIVE RD SHARMA ENGLISH-HEIGHTS AND DISTANCES-Exercise
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  2. A ladder rests against a vertical wall at angle alpha to the horizonta...

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  3. From the top of a cliff 300 metres high, the top of a tower was obser...

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  4. The angles of elevation of the top of a tower at the top and the foot ...

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  5. A person standing on the bank of a river finds that the angle of elev...

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  6. A tower subtends an angle of 30^@ at a point on the same level as the ...

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  7. AB is a vertical pole. The end A is on the level ground .C is the midd...

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  8. The angle of depression of a point situated at a distance of 70 metres...

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  9. The angle of elevation of the top of a vertical tower from two points ...

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  10. An aeroplane flying horizontally 1 km above the ground is observed ...

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  11. about to only mathematics

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  12. At a distance 12 metres from the foot A of a tower AB of height 5 met...

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  13. A tower 50 m high , stands on top of a mount, from a point on the grou...

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  14. A person on a ship sailing north sees two lighthouses which are 6 km a...

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  15. An observer finds that the elevation of the top of a tower is 22.5^@ a...

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  16. A vertical lamp-post, 6m high, stands at a distance of 2 m from a wall...

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  17. The angle of elevation of the top of a vertical pole when observed ...

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  18. The upper 3/4 th portion of a vertical pole subtends an angle theta su...

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  19. A person standing on the bank of a river observes that the angle of ...

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  20. A tower subtends angles alpha,2alpha,3alpha respectively, at point A ,...

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