An aqueous solution of 6.3 g oxalic acid dehydrate is made upto 250 mL. The volume of 0.1 N NaOH required to completely neutralize 10 mL of this solution is

Options

A. 40 mL
B. 20 mL
C. 10 mL
D. 4 mL

Answer

A

Explanation

Normality for oxalic acid `= (6.3//63)/250 xx1000=0.1 xx 4 = 0.4 N`
Applying, `N_1V_1 = N_2V_2 implies 0.4 xx 10 = 0.1 xxV_2`
`V_2=(0.4xx10)/0.1 = 40 mL`