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An aqueous solution of 6.3 g oxalic acid...

An aqueous solution of 6.3 g oxalic acid dehydrate is made upto 250 mL. The volume of 0.1 N NaOH required to completely neutralize 10 mL of this solution is

A

40 mL

B

20 mL

C

10 mL

D

4 mL

Text Solution

Verified by Experts

The correct Answer is:
A

Normality for oxalic acid `= (6.3//63)/250 xx1000=0.1 xx 4 = 0.4 N`
Applying, `N_1V_1 = N_2V_2 implies 0.4 xx 10 = 0.1 xxV_2`
`V_2=(0.4xx10)/0.1 = 40 mL`
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Knowledge Check

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