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A solution weighing 'a'g has molality 'b...

A solution weighing 'a'g has molality 'b'. The molecular mass of solute, if the mass of solute is 'c' g, will be

A

`c/b xx 100/((a-c))`

B

`b/a xx 1000/((a-b))`

C

`b/c xx 1000/((a-c))`

D

`c/a xx 1000/((b-a))`

Text Solution

Verified by Experts

The correct Answer is:
A
Molality, `m= w_B/m_B xx 1000/w_A`
`b= C/m_b xx 1000/((a-c)), m_B = c/b xx 1000/((a-c))`
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