How many gram of dibasic acid (molecular weight 200) should be present in 100 mL of the aqueous solution to give 0.1 normality?

Options

A. lg
B. 2 g
C. 10 g
D. 20 g

Answer

A

Explanation

Equivalent weight `= ("Molecular weight")/("Basicity") =200/2 = 100`
Normality `=("Weight")/("Equivalent weight") xx 1000/("Volume of solution (in mL)")`
Weight of solute =`(0.1 xx 100 xx 100)/1000 =1g`