The vapour pressure lowering of a solven...

The vapour pressure lowering of a solvent is proportional to

the mole fraction of the solute

the mole fraction of the solvent

the molality of the solvent

the normality of the solution.

Text Solution

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The correct Answer is:

`(P^@-P_s)/(P^@) = X_2` (Raoult.s law)

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