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A 0.0020 m aqueous solution of an ionic ...

A 0.0020 m aqueous solution of an ionic compound `[CO(NH_3)_5 (NO_2)]CI` freezes at -0.00732 `""^@C`. Number of moles of ions in which I mol of ionic compound produces on being dissolved in water will be `(K_f = -1.86^@C//m)`

A

3

B

4

C

1

D

2

Text Solution

Verified by Experts

The correct Answer is:
D

The number of moles of ions produced by 1 mole of ionic compound = I
Applying, `DeltaT_f = ixx K_f xxm`
`0.00732=ixx1.86xx0.002 implies (0.00732)/(1.86 xx 0.002) = 1.96~~2`
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0.002m aqueous solution of an ionic compound Co(NH_(3))_(5)(NO_(2))CI freezes at -0.00732^(@)C .Number of moles of ions which 1 mole of ionic compound produces in water will be (K_(f) = 1.86^(@)C//m)

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