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The van't Hoff factor for 0.1 M Ba(NO3)2...

The van't Hoff factor for 0.1 M `Ba(NO_3)_2` solution is 2.74. The degree of dissociation is

A

0.913

B

0.74

C

0.87

D

1

Text Solution

Verified by Experts

The correct Answer is:
C
Degree of dissociation `(alpha)=(i-1)/(n-1)`
n is number of ions produces from one molecule
`alpha = (2.74-1)/(3-1)= (1.74)/2 =0.87 implies` Degree of dissociation = 87%
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