A solution prepared by dissolving 15 g o...

A solution prepared by dissolving 15 g of non-volatile solute in 270 g of water gave relative lowering of vapour pressure of 0.005. The molecular weight of the solute is

324

200

225

Text Solution

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The correct Answer is:

`M_2 =(W_2M_1)/W_1 xx(P^@/(P^@-P_s))` where, symbols have their usual meaning
`M_2 = (15xx18)/270 xx1/(0.005) = 200`

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