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Calculate the boiling point of a solutio...

Calculate the boiling point of a solution made by dissolving 38.5 g of a solute of molecular weight 154 in 250 g of benzene if boiling point of pure benzene is `80.1^@C and K_b` for benzene is `2.61^@C m^(-1)`

A

`85.32^@C`

B

`74.88^@C`

C

`77.49^@C`

D

`82.71^@C`

Text Solution

Verified by Experts

The correct Answer is:
D

Molality of solvent =`(38.5)/154 xx 1000/250 = 1`
`DeltaT_b = K_b.m = 2.61xx1 = 2.61^@C`
`DeltaT_b = T_b-T_b^@`
`T_b = DeltaT_b + T_b^@ = 2.61+80.1 = 82.71^@C`
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