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A 0.0020 in aqueous solution of an ionic...

A 0.0020 in aqueous solution of an ionic compound `[CO(NH_3)_5(NO_2)]Cl` freezes at `-0.00732^@C`. Number of moles of ions which I mol of ionic compound produces on being dissolved in water will be `(K_f = -1.86^@C//m)`

A

3

B

4

C

1

D

2

Text Solution

Verified by Experts

The correct Answer is:
D

The number of moles of ions produced by 1 mol of ionic compound = i
Applying, `DeltaT_f=i xx k_f xxm, 0.00732 = -i xx 1.86 xx 0.002`
`implies i =(0.00732)/(1.86xx0.002) = 1.96=2`
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