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At a given place on the earth's surface,...

At a given place on the earth's surface, the horizontal component of earth's magnetic field is `3 xx 10^(-5)` T and resultant magnetic field is `6 xx 10^(-5)` T. The angle of dip at this place is

A

`30^(@)`

B

`40^(@)`

C

`50^(@)`

D

`60^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
`AsH=Rcosdelta " ":." "cosdelta=(H)/(R)=(3xx10^(-5))/(6xx10^(-5))=(1)/(2)`
`:. Delta=60^(@)`
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